Exam 1 (Early) - 2008

Exam 1 (Early) - 2008 - CHEM 188 Spring 2008 Hour Exam...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
CHEM 188 – Spring, 2008 Hour Exam 1 (Early) February 13, 2008 Instructions: Your scantron answer sheet must show your NAME , 7-DIGIT KU ID NUMBER , and LAB SECTION . (Begin these entries at the LEFT end of the space provided.) In answering the questions, be careful to fill in the corresponding circles on the answer sheet according to the number of the question on the exam. USE A SOFT (No. 2) PENCIL .  Useful information: Gas constant, R = 8.314 J/K mol = 0.08206 L atm/K mol Integrated Rate Laws: kt [A] 1 [A] 1 : order Second e [A] [A] : order - First kt - [A] [A] : order - Zero 0 kt 0 0 + = - = = - Arrhenius equation: /RT -E a Ae k = - = 2 1 2 1 a 2 1 T T T T R E k k ln Relation of K P to K C : K P = K C (RT) n 1. For the reaction 4NO 2 (g) + O 2 (g) 2N 2 O 5 (g) the rate of loss of molecular oxygen, -d[O 2 ]/dt is 0.024 M/s at a particular time during the reaction. What is the rate, d[N 2 O 5 ]/dt , at which N 2 O 5 is being formed? A. 0.012 M/s B. 0.024 M/s C. 0.036 M/s D. 0.048 M/s E. none of these 1
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern