# Ch06s - Chapter 6 Problem Solutions 6.1 a gm = r = r0 = I...

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Chapter 6 Problem Solutions 6.1 a. ( )( ) 0 0 2 76.9 mA/V 0.026 180 0.026 2.34 k 2 150 75 k 2 CQ m m T T CQ A CQ I g g V V r r I V r r I π π β = = = = = = Ω = = = Ω b. ( )( ) 0 0 0.5 19.2 mA/V 0.026 180 0.026 9.36 k 0.5 150 300 k 0.5 m m g g r r r r π π = = = = Ω = = Ω 6.2 (a) ( )( ) 0.8 30.8 mA/V 0.026 120 0.026 3.9 K 0.8 120 150 K 0.8 CQ m T T CQ A o CQ I g V V r I V r I π β = = = = = = = = = (b) ( )( ) 0.08 3.08 mA/V 0.026 120 0.026 39 K 0.08 120 1500 K 0.08 m o g r r π = = = = = = 6.3 ( )( ) 0 0 200 5.2 mA 0.026 125 0.026 0.625 k 5.2 200 38.5 k 5.2 CQ CQ m CQ T T CQ A CQ I I g I V V r r I V r r I π π β = = = = = = Ω = = = Ω 6.4

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( ) 80 2.08 mA 0.026 0.026 1.20 96 2.08 CQ CQ m CQ T T CQ I I g I V V r I π β β β = = = = = = 6.5 (a) ( )( ) ( )( ) 2 0.7 0.0052 250 120 0.0052 0.624 0.624 24 / 0.026 120 0.026 5 0.624 BQ C m m o I mA I mA g g mA V r r k r π π = = = = = = = = Ω = ∞ (b) ( )( ) 5 24 4 1.88 5 250 v m C v B r A g R A r R π π = − = − = − + + (c) 0.426sin100 1.88 O O S S v v v v v t V A = = = − 6.6 , 1.08 1.32 mA CQ m CQ T I g I V = 1.08 1.32 41.5 50.8 mA/V 0.026 0.026 m m g g ( ) ( )( ) ( ) ( )( ) 120 0.026 ; max 2.89 k 1.08 80 0.026 min 1.58 k 1.32 1.58 2.89 k T CQ V r r I r r π π π π β = = = Ω = = Ω Ω 6.7 a. ( )( ) ( ) ( ) ( ) ( )( ) 120 0.026 5.4 0.578 mA 1 1 5 2.5 V 2 2 2.5 5.0 0.578 4.33 k 0.578 0.00482 mA 120 on 0.00482 25 0.70 0.820 V T CQ CQ CQ CEQ CC CEQ CC CQ C C C CQ BQ BB BQ B BE BB V r I I I V V V V I R R R I I V I R V V π β β = = = = = = = = = = Ω = = = = + = + = b.
( )( ) ( ) ( ) ( ) ( ) ( )( ) 0 0 0 0 0 120 0.026 5.40 k 0.578 0.578 22.2 mA/V 0.026 100 173 k 0.578 , 120 173 4.33 120 4.22 16.7 5.40 25 30.4 T CQ CQ m T A CQ m C S B C v m C B B v v V r I I g V V r I r V g r R V V V r R r R r A g r R r R r R A A π π π π π π π π β β = = = Ω = = = = = = Ω = − = + = − = − + + = − = − = − + 6.8 a. ( ) ( ) ( ) ( )( ) 1 5 V 2 10 5 10 0.5 10 k 0.5 0.005 100 on 0.70 0.005 50 0.95 V ECQ CC ECQ CQ C C C CQ BQ EB BQ B BB BB V V V I R R R I I V I R V V β = = = = = Ω = = = + = = + = b. ( )( ) 0 0 0.5 19.2 mA/V 0.026 100 0.026 5.2 k 0.5 0.5 CQ m m T T CQ A CQ I g g V V r r I V r r I π π β = = = = = = Ω = = = ∞ c. ( )( ) 100 10 18.1 5.2 50 π β = − = − = − + + C v v B R A A r R 6.9 ( )( ) ( ) ( ) 10 4 1.5 mA 4 1.5 0.015 mA 100 100 0.026 1.73 K 1.5 5sin mV 2.89sin A 1.73 k CQ BQ be b I I r t v i t r π π ω ω μ = = = = = = = = = Ω So

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( ) ( ) ( ) ( ) ( ) ( ) ( ) [ ] ( ) ( ) ( ) ( ) ( ) 1 1 1 1 15 2.89sin A 1.5 0.289sin mA 10 10 1.5 0.289sin 4 1.156sin 1.156 231 0.005 B BQ b C B C C C C C C v v be i t I iE t i t i i t t v t i t R t v t t v v t A A v t ω μ β ω ω γ ω = + = + = = + = = + = = = = − 6.10 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1.2sin V 1.2sin 0 2 0.60sin mA 6sin A 100 2 K 50 12sin mV o C C o C C C b be b m be v t t i t R v i t i t t i t i t t v t i t r g r r v t t π π π ω ω ω ω μ β β ω = + = = = − = = − = = = = = − 6.11 a. CQ EQ I I ( ) ( ) 5 10 10 1.2 0.2 CEQ CQ C E CQ V I R R I = = + = + 3.57 mA 3.57 0.0238 mA 150 CQ BQ I I = = = ( )( ) ( )( )( ) 1 2 0.1 1 0.1 151 0.2 3.02 k TH E R R R R β = = + = = Ω & ( ) ( ) ( ) ( )( ) ( )( ) ( )( )( ) ( ) 1 1 1 1 2 2 2 1 10 5 on 1 5 1 3.02 10 5 0.0238 3.02 0.7 151 0.0238 0.2 5 1 30.2 1.50 20.1 20.1 3.02 3.55 k 20.1 TH TH BQ BQ E TH TH BE V R R V I R V I R R R k R R R R β + = = + + = + + = = Ω = = Ω + b. ( )( ) 150 0 026 1 09 k 3 57 3 57 137 mA/V 0 026 m . r . . . g . = = Ω = = p