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# Ch05s - Chapter 5 Problem Solutions 5.1(a iC 510 = = 85 6...

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Chapter 5 Problem Solutions 5.1 (a) ( ) ( )( ) 510 85 6 85 0.9884 1 86 1 86 6 516 C B E B E i i i i i A β β β α α β β μ = = = = = = + = + = = (b) ( ) ( )( ) 2.65 53 0.050 53 0.9815 54 1 54 0.050 2.70 E B E i i i mA β β α α β = = = = = + = = 5.2 (a) For 110: β = 110 0.99099 1 111 β α β = = = + For 180: β = 180 0.99448 181 α = = 0.99099 0.99448 α (b) ( ) 110 50 A 5.50 C B C I I I mA β μ = = = or ( ) 180 50 A 9.00 C C I I mA μ = = so 5.50 9.0 C I mA 5.3 (a) ( ) 1.12 9.33 A 120 121 1.12 1.13 mA 120 120 0.9917 121 B E i i μ α = = = = = (b) ( ) 50 2.5 mA 20 21 50 52.5 mA 20 20 0.9524 21 B E i i α = = = = = = 5.4 (a) α 1 α β α = 0.9 9 0.95 19 0.98 49 0.99 99 0.995 199 0.999 999 (b)

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β 1 β α β = + 20 0.9524 50 0.9804 100 0.9901 150 0.9934 220 0.9955 400 0.9975 5.5 (a) ( ) ( )( ) 1.2 14.8 A 81 80 1.2 1.185 mA 81 80 0.9877 81 5 1.185 2 2.63 V B C C I I V μ α = = = = = = = (b) ( ) ( )( ) 0.80 9.88 A 81 80 0.80 0.790 mA 81 80 0.9877 81 5 0.790 2 3.42 V B C C I I V μ α = = = = = = = (c) Yes, C B V V > so B-C junction is reverse biased in both areas. 5.6 For 5 0, 2.5 mA 2 C C V I = = = 2.5 2.546 mA 0.982 C E E I I I α = = = 5.7 (a) ( ) ( )( ) 0.75 12.3 A 61 60 0.75 0.738 mA 61 60 0.9836 61 10 0.738 5 10 6.31 V B C C C C C I I V I R V μ α = = = = = = = = − (b) ( ) ( )( ) 1.5 24.6 A 61 60 1.5 1.475 mA 61 60 0.9836 61 1.475 5 10 2.625 V B C C C I I V V μ α = = = = = = = − (c) Yes, 0 C V < in both cases so that B-C junction is reverse biased.