Ch04p - Chapter 4 Exercise Solutions EX4.1 g m = 2 K n(VGS...

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Chapter 4 Exercise Solutions EX4.1 ( ) ( ) ( ) ( )( ) 2 2 2 and 0.75 0.5 0.8 2.025 2 0.5 2.025 0.8 1.22 / 1 1 (0.01)(0.75) 133 133 m n GS TN D n GS TN GS GS m m o DQ o g K V V I K V V V V V g g mA V r I k r k λ = = = = = = = = = Ω = Ω EX4.2 ( )( ) ( )( ) 2 2 0.5 0.4 0.8944 mA/V 0.8944 10 8.94 v m D m n DQ v A g R g K I A = − = = = = − = − EX4.3 (a) ( ) ( ) ( )( ) 2 1 2 2 320 5 1.905 V 520 320 0.20 1.905 0.8 0.244 mA 2 2 0.2 0.244 0.442 mA/V GS DD DQ m n DQ o R V V R R I g K I r = = = + + = = = = = = ∞ (b) ( )( ) 0.422 10 4.22 v m D A g R = − = − = − (c) 1 2 520 320 198 K i R R R = = = & & (d) 10 K O D R R = = EX4.4 ( ) ( ) ( ) ( ) ( ) ( ) 2 2 2 At transition point, 1 mA sat 1 0.2 sat sat 2.236 V D D n GSt TN n DS DS DS I I K V V K V V V = = = = = ( ) ( ) 2 2 1 2 1 2 1 5 2.236 Want 2.236 3.62 V 2 5 3.62 2.76 K 0.5 0.5 0.2 0.8 2.38 V 1 DSQ D GSQ GSQ GSQ DD DD V R V V R V V R R V R R R = + = = = = = = = + & ( )( ) 1 2 1 1 So 2.38 200 5 420 K and 382 K R R R = = =
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