Ch02s - Chapter 2 Problem Solutions 2.1 I 0 R 1K I 10 0 10...

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Chapter 2 Problem Solutions 2.1 R 1 K I 0 10 0 10 I 0.6 V, 20 f V r = = Ω γ ( ) ( ) 0 0 For 10 V, 10 0.6 1 9.4 1 0.02 9.22 I f R v v R r v = = + = + = 0 9.22 0.6 10 2.2 R D I 0 D 0 0 0 0 ln and ln I D D D T D S I T S v v v v i v V i I R v v v V I R = = = = 2.3 (a) 80sin 13.33sin 6 s t v t ω ω = = Peak diode current 13.33 (max) d i R =
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(b) (max) 13.3 V s PIV v = = (c) ( ) [ ] ( ) ( ) 1 1 ( ) 13.33sin 2 13.33 13.33 13.33 cos 1 1 2 2 4.24 o T o o o o o o o v avg v t dt dt T x v avg V π π π π π π = = × = = − − − = =