HW1 solutions - Solutions to Unit 1 Homework No 1 1(a K Z=...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Solutions to Unit 1 Homework No. 1 1. (a) ( 29 RT R K RT Z σ α - β - σ σ = σ Π = A plot of Z versus : The two partial derivatives are: β - σ = Π σ K T , and ( 29 3 2 T 2 K σ α + β - σ - = σ Π ( 29 σ σ α + β - σ - β - σ = Π d 2 K dT K d 3 2 2. The total differential of P is: dn n P dT T P dV V P dP T V V n T n , , , + + = We can determine each partial derivative. The total differential is then: dn V RT dT V nR dV V nRT dP + + - = 2 , which can then be approximated as: n V RT T V nR V V nRT P + + - 2 1 Z Π A very slight dip due to very weak hydrophobic attractive interactions at low surface pressure A sharp increase in Z at higher surface pressures when the inter- headgroup repulsions become significant
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 2 3 3 1 1 3 1 1 3 3 2 3 1 1 10 779 1 0015 0 020000 0 15 298 3144 8 0000 1 85 0 020000 0 15 298 3144 8 0000 1 10 200 0 020000 0 15 298 3144 8 0000 1 - - - - - - - - × + + × - - Nm . mol . m . K . mol JK . mol . K . m . K . mol JK . mol .
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern