Aprocesshasthefo llowingtransfer funct ion g s 4 1 as

Unformatted text preview: 3 respectively. Or, you can just use the “Bode” command in MATLAB. B ode Diagrams Fr om: U( 1) 0 --- g2(s ) __ g1(s ) - 100 - 150 0 To: Y (1) Phas e (deg); Magnitude (dB) - 50 - 100 --- g2(s ) __ g1(s ) - 200 - 300 10-1 100 101 102 Frequenc y (rad/ s ec ) V. A process has the fo llowing transfer funct ion: g ( s = ) 4 + 1 (as ) (5 + 1 ( + 1 ) s ) s ) For the fo llowing values of the parameter a, · a = 10 · a = 2 · a = 0. 5 · a = -1 Compute the responses for a step­change o f magnitude 0.5 and plot in a single figure. What conclusio ns can you draw concerning the zero location? Is the locat ion of the po le corresponding to t 2 = 5 important? Solution: Note that the zero is located at: z = 1 / a Using the fo llowing mat lab m­file, TF=30; a=10; n=[2*a 2]; d=[conv([5 1],[1 1])]; g=tf(n,d); step(g,TF); hold on a=2; n=[4*a 4]; g=tf(n,d); step(g,TF); hold on a=0.5; n=[4*a 4]; g=tf(n,d); step(g,TF); hold on a=­1; n=[4*a 4]; g=tf(n,d); step(g,TF); We can generate the fo llowing figure: 3.5 3...
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