Assignment 4 Solutions 2009

15 then c 015s the so lution in time do main can be

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Unformatted text preview: (V / q + 1 ÷ ÷ c ( s i =1 c -1 ( s è )s ø 0) i ) 5 If the input is changed by 0.15, then c ( = 0 15 / s , the so lution in time do main can be written . 0 s) using partial fraction expansio ns, leading to the standard result (with V / q = 10 ), 1 2 3 4 é æ t 1 æ t ö 1 æ t ö 1 æ t ö ö ù - t / 10 ç c ( ) = 0 ê1 - e .15 1 + + ç ÷ + ç ÷ + ç ÷ ÷ú 5 t ç 10 2 è 10 ø ! 3 è 10 ø ! 4 è 10 ø ÷ ú ! ê è øû ë \ Concentration after each tank can now be calculated, [ c1 (30 = 0 7 + 0 15 1 - e -30 / 10 = 0 8425 ) . . . And others fo llow: c 2 ( ) = 0 8201 30 . c ( ) = 0 7865 . 3 30 c 4 ( ) = 0 7529 30 . c ( ) = 0 7277 . 5 30 2. Draw the Bode diagrams of the transfer funct ions below, g ( s = 1) 1 (3 + 1)( + 1) s s g 2 ( s = ) 1 (3 + 1)( + 1)( . s + 1) s s 0 1 Comment on the differences observed in the diagrams and their practical implicat ions. Solution: To draw the Bode diagrams, use the fo llowing steps: ü ü ü ü ü ü Replace s = jw in the transfer funct ion Find the magnitude (AR) of the comp...
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This note was uploaded on 01/12/2014 for the course CHE 4198 taught by Professor Hjortso,m during the Fall '08 term at LSU.

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