practice exam c

1 2 s s1 2 accordingly you have evaluated ln u sin

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Unformatted text preview: us−1 · with respect to ln u sin π s − cos π s π As it turns out, C equals +∞ du = λs−1 π 1 . 1−λ 2 + s λs−1 π2 Accordingly, you have evaluated ln u sin π s − cos π s π ln u du = . 2 + du π2 = . 7 : + C. Line #: 23590. Name : ID # : ([III] continued) (3a) Substitute s=0 in your answer in (2), then negate the whole quantity, and thereby evaluate +∞ u=0 1 u u+λ · ln u 2 du + π2 = . (3b) Substitute s=1 +∞ u=0 in your answer in (2), and thereby evaluate 1 u+λ · ln u 2 du + π2 = . 8...
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This note was uploaded on 01/12/2014 for the course MATH 116 taught by Professor Scholle,minho during the Fall '08 term at Kansas.

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