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Unformatted text preview: ve formula to evaluate Γ 1
2 =
. Work for (1). 5 . Line #: 23590. Name : ID # : ([III] continued)
(2) Realize that in (1) above you have evaluated Γ 1
2 +∞ = 1 t− 2 e−t dt. t=0 Use this information to evaluate the improper integral: +∞ 2 e−x dx = x=0 . Work for (2). 6 Line #: 23590. Name : ID # : [IV] (30pts) Let a be a constant, with a > 1. “ An antiderivative of fx 2 = Know
a2 − a a − x2 Fx Use this fact for 2
= arctan 1
√
2 √
3
2 x=0 = 3
2 a= − x2 a2 − a x
a− 2a − 1...
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This note was uploaded on 01/12/2014 for the course MATH 116 taught by Professor Scholle,minho during the Fall '08 term at Kansas.
 Fall '08
 SCHOLLE,MINHO
 Calculus

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