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ISM_Chapter_09

# ISM_Chapter_09 - Chapter 9 9.1a 1/6 b 1/6 9.2 a 1 X P =...

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Unformatted text preview: Chapter 9 9.1a. 1/6 b. 1/6 9.2 a ) 1 X ( P = =P(1,1)= 1/36 b ) 6 X ( P = = P(6,6) = 1/36 9.3a P( X = 1) = (1/6) 5 = .0001286 b P( X = 6) = (1/6) 5 = .0001286 9.4 The variance of X is smaller than the variance of X. 9.5 The sampling distribution of the mean is normal with a mean of 40 and a standard deviation of 12/ 100 = 1.2. 9.6 No, because the sample mean is approximately normally distributed. 9.7 a ) 1050 X ( P = - - 16 / 200 1000 1050 n / X P = P(Z &amp;gt; 1.00) = .5 P(0 &amp;lt; Z &amp;lt; 1.00) = .5 .3413 = .1587 b = &amp;lt; ) 960 X ( P - &amp;lt; - 16 / 200 1000 960 n / X P = P(Z &amp;lt; .80) = .5 P(0 &amp;lt; Z &amp;lt; .80) = .5 .2881 = .2119 c = ) 1100 X ( P - - 16 / 200 1000 1100 n / X P = P(Z &amp;gt; 2.00) = .5 P(0 &amp;lt; Z &amp;lt; 2.00) = .5 .4772 = .0228 9.8 a ) 1050 X ( P = - - 25 / 200 1000 1050 n / X P = P(Z &amp;gt; 1.25) = .5 P(0 &amp;lt; Z &amp;lt; 1.25) = .5 .3944 = .1056 b = &amp;lt; ) 960 X ( P - &amp;lt; - 25 / 200 1000 960 n / X P = P(Z &amp;lt; 1.00) = .5 P(0 &amp;lt; Z &amp;lt; 1.00) = .5 .3413 = .1587 c = ) 1100 X ( P - - 25 / 200 1000 1100 n / X P = P(Z &amp;gt; 2.50) = .5 P(0 &amp;lt; Z &amp;lt; 2.50) = .5 .4938 = .0062 9.9 a ) 1050 X ( P = - - 100 / 200 1000 1050 n / X P = P(Z &amp;gt; 2.50) = .5 P(0 &amp;lt; Z &amp;lt; 2.50) = .5 .4938 = .0062 197 b = &amp;lt; ) 960 X ( P - &amp;lt; - 100 / 200 1000 960 n / X P = P(Z &amp;lt; 2.00) = .5 P(0 &amp;lt; Z &amp;lt; 2.00) = .5 .4772 = .0228 c = ) 1100 X ( P - - 100 / 200 1000 1100 n / X P = P(Z &amp;gt; 5.00) = 0 9.10 a = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 4 / 5 50 52 n / X 4 / 5 50 49 P = P(.40 &amp;lt; Z &amp;lt; .80) = P(0 &amp;lt; Z &amp;lt; .40) + P(0 &amp;lt; Z &amp;lt; .80) = .1554 + .2881 = .4435 b = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 16 / 5 50 52 n / X 16 / 5 50 49 P = P(.80 &amp;lt; Z &amp;lt; 1.60) = P(0 &amp;lt; Z &amp;lt; .80) + P(0 &amp;lt; Z &amp;lt; 1.60) = .2881 + .4452 = .7333 c = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 25 / 5 50 52 n / X 25 / 5 50 49 P = P(1.00 &amp;lt; Z &amp;lt; 2.00) = P(0 &amp;lt; Z &amp;lt; 1.00) + P(0 &amp;lt; Z &amp;lt; 2.00) = .3413 + .4772 = .8185 9.11 a = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 4 / 10 50 52 n / X 4 / 10 50 49 P = P(.20 &amp;lt; Z &amp;lt; .40) = P(0 &amp;lt; Z &amp;lt; .20) + P(0 &amp;lt; Z &amp;lt; .40) = .0793 + .1554 = .2347 b = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 16 / 10 50 52 n / X 16 / 10 50 49 P = P(.40 &amp;lt; Z &amp;lt; .80) = P(0 &amp;lt; Z &amp;lt; .40) + P(0 &amp;lt; Z &amp;lt; .80) = .1554 + .2881 = .4435 c = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 25 / 10 50 52 n / X 25 / 10 50 49 P = P(.50 &amp;lt; Z &amp;lt; 1.00) = P(0 &amp;lt; Z &amp;lt; .50) + P(0 &amp;lt; Z &amp;lt; 1.00) = .1915 + .3413 = .5328 9.12 a = &amp;lt; &amp;lt; ) 52 X 49 ( P - &amp;lt; - &amp;lt;- 4 / 20 50 52 / 4 / 20 50 49 n X P = P(.10 &amp;lt; Z &amp;lt; .20) = P(....
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ISM_Chapter_09 - Chapter 9 9.1a 1/6 b 1/6 9.2 a 1 X P =...

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