536o 5 8 2 3 i1 12 7 2 cos 314 t 30 a i 2 11

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Unformatted text preview: 达方式: Im i = I m cos(ωt + ψ i ) ψi < 0 ψi i = I m sin(ωt + ψ i + 90°) 正弦量的三要素:I m − −振幅 ω = 2πf − −电角频率 ψ i − −初相位 相量: & I = Ie jψ i = I∠ψ i +j 相量的模=正弦量的有效值 相量辐角=正弦量的初相角 相量图: ψi & I ψi & I +1 4 复数的运算: 例1. 5∠47 o + 10∠ − 25 o = ? 解: 5∠47 + 10∠ − 25 = (3.41 + j 3.657) + (9.063 − j 4.226) o o = 12.47 − j 0.569 = 12.48∠ − 2.61o 例2. (17 + j 9) (4 + j 6) 220 ∠ 35 + =? 20 + j 5 o 19.24∠27.9o × 7.211∠56.3o...
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