CH11_非正弦周期电流电路和信号

5 2 cos t 64 862 2 cos 3t 1017 a 5 p u 0

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Unformatted text preview: 7 例2: 设某无源二端网络的电 压、电流为: u = 50 + 84.6 cos( ωt + 30° ) + 56.6 cos( 2ωt + 10° )V i = 1 + 0.707 cos( ωt − 20° ) + 0.424( 2ωt + 50° ) A , u、i为关联方向,求二端口 吸收的平均功率。 解: 80.46 0.707 ⋅ P = 50 ⋅ 1 + cos( 30° + 20° ) + 2 2 56.6 0.424 ⋅ cos( 10° − 50° ) = 78.5W 2 2 只有同频率的正弦量才构成平均功率 8 四、非正弦周期电流电路的计算 非正弦周期电流电路的计算的具体步骤是:...
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