Since mathematica reserves upper case letters for

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Unformatted text preview: of z = 1 of length at least π . It follows that the solution to (5.31) must have infinitely many zeros in the region z > 1, and J0 (x) must have infinitely many positive zeros, as claimed. The fact that Jn (x) has infinitely many positive zeros could be proven in a similar fashion. 149 Exercises: 5.8.1. Solve the following initial value problem for the heat equation in a disk: Find u(r, θ, t), 0 < r ≤ 1, such that ∂u 1∂ = ∂t r ∂r r ∂u ∂r u(r, θ + 2π, t) = u(r, θ, t), + 1 ∂2u , r2 ∂θ2 u well-behaved near r = 0, u(1, θ, t) = 0, u(r, θ, 0) = J0 (α0,1 r) + 3J0 (α0,2 r) − 2J1 (α1,1 r) sin θ + 4J2 (α2,1 r) cos 2θ. 5.8.2. Solve the following initial value problem for the vibrating circular membrane: Find u(r, θ, t), 0 < r ≤ 1, such that ∂2u 1∂ = ∂t2 r ∂r u(r, θ + 2π, t) = u(r, θ, t), r ∂u ∂r + 1 ∂2u , r2 ∂θ2 u well-behaved near r = 0, ∂u (r, θ, 0) = 0, ∂t u(r, θ, 0) = J0 (α0,1 r) + 3J0 (α0,2 r) − 2J1 (α1,1 r) sin θ + 4J2 (α2,1...
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This document was uploaded on 01/12/2014.

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