# We also obtain the condition h g x 0 which is just our

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: asis for R n . We will see that these complications do not occur for symmetric matrices. Spectral Theorem.1 Suppose that A is a symmetric n × n matrix with real entries. Then its eigenvalues are real and eigenvectors corresponding to distinct eigenvectors are orthogonal. Moreover, there is an n × n orthogonal matrix B of determinant one such that B −1 AB = B T AB is diagonal. Sketch of proof: The reader may want to skip our sketch of the proof at ﬁrst, returning after studying some of the examples presented later in this section. We will assume the following two facts, which are proven rigorously in advanced courses on mathematical analysis: 1. Any continuous function on a sphere (of arbitrary dimension) assumes its maximum and minimum values. 2. The points at which the maximum and minimum values are assumed can be found by the method of Lagrange multipliers (a method usually discussed in vector calculus courses). 1 This is called the “spectral theorem” because the spectrum is another name for the set of eigenvalues of a matrix. 30 The equation of the sphere S n−1 in R n is x...
View Full Document

## This document was uploaded on 01/12/2014.

Ask a homework question - tutors are online