We imagine that the force acting on the portion of

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Unformatted text preview: his eigenvalue problem. b. Find the general solution to the heat equation ∂u ∂2u = ∂t ∂x2 subject to the mixed boundary condition (4.15). c. Find the function u(x, t), defined for 0 ≤ x ≤ π and t ≥ 0, such that: ∂u ∂2u , = ∂t ∂x2 4.3 u(0, t) = ∂u (π, t) = 0, ∂x u(x, 0) = 4 sin(x/2) + 12 sin(3x/2). Numerical solutions to the heat equation There is another method which is sometimes used to treat the initial value problem described in the preceding section, a numerical method based upon “finite differences.” Although it yields only approximate solutions, it can be applied in some cases with variable coefficients when it would be impossible to apply Fourier analysis in terms of sines and cosines. However, for simplicity, we will describe only the case where ρ and k are constant, and in fact we will assume that c2 = L = 1. Thus we seek the function u(x, t), defined for 0 ≤ x ≤ 1 and t ≥ 0, which solves the heat equation ∂u ∂2u = ∂t ∂x2 subject to the boundary conditions u(0, t) = u(1, t) = 0 and the initial con...
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This document was uploaded on 01/12/2014.

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