PHYS4final

PHYS4final - Physics 4 Final, Saturday, March 22, 2008...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Physics 4 Final, Saturday, March 22, 2008 Name: Solfix‘o V'LS Seat: Exam form A Do not begin until instructed to do so. You may use a calculator and one (double—sided) page of hand-written notes. 1. (10 points) Answer the following true or false questions. . @or F) 2 X a = 3}. . (T or®(3:fi + 42) x (5:5)) = 152. o (T or The index of refraction of air is larger than the index of refractlon of water. 0 1" F) If you place a voltage across a resistor, it will produce a magnetic field. Y4; bamufit H- will Pt‘Oq‘UCe. a. Curran/Vt o {T or® Light moving in air will undergo total internal reflection on a water surface it the angle of incidence is high enough. 2. (2 points) A piano—convex lens is made from a glass sphere of radius R 10 cm by grinding away part of the Sphere as shown below. The lens is the remainder of the Sphere} with a maximum thickness of R — d = 2 cm. For light that then moves through the lens beginning from the flat side, what is the focal length of the lens? (a) 5 cm (b) 0.4 cm (c) 0.05 cm (d) 20 cm (e) 10 cm (f) 1 cm (g) -5 cm (h) —0.4 cm -005 cm@k) —10 cm (1) —1 cm .L __.L %3(udl)[ R; BL) 14L L:[5'"l>(a‘lr”}% 1;_ “0.5 5 -0-05‘ " 73 ._10 M 3. (4 points) The figures below show interference patterns as intensity vs angle. For each of the descriptions of slit arrangements listed in the left column choose the letter of the best matching figure in the right column. i a A single slit of width 0: < A. (a.@, c, d) o A single slit of width (1 > A. (a, b, c, :- A grating of two slits of width 0. < A. b. c, d) o A grating of many slits of width (1 < A. (a, b, @d) 4. (4 points) The figure below shows two rays of light, of wavelength 600 nrn, that reflect from glass surfaces separated by 150 nm. The rays are initially in phase. When they have cleared the reflection region, are the rays: exactly in phase, xactl out of phase or half way between? :l-h-150nm—H: T‘U- “Pillar [Pad/LL M4. [hmk Plane-*- 5 “iii- —— z?!“ 3 ““"~- .. D‘F fl (2- [5-0 mm.) 3 aoomm I“ n— 1 so mg m V M 6* PM“ 5. (15 points) A thin glass rod of length L has a charge Q uniformly distributed over its surface. The rod is moving along the :1: axis at a speed 1: toward the positive ac direction. Calculate the magnetic field produced at a point on the y axis, i.e. at (0,y, 0), for the instant in time when one end of the rod is at the origin and the other end is at a: = L. You must show and explain all steps, but you can stop when you get to the point that “the rest of the calculation could be looked up fromarnath table.” Tild- (5 WI. We. 7L0 Ag; ,uo Ag 31.? when Jab; L A ‘9 +11 Er {~7- clurzaa. its m.‘.§L,v—Ml? \51‘1" U "* i Zc¢/-M"‘*5) \7 Amen}: Funds in 44¢... x Amuhw afar a! §I10 Sc) M W 4-? avg; afolwxc+cw j 9‘ {’3 Fla?th (“ML ~2- A 3*»; 3 “EM”: _ V6659 2 WW 5% = x/c‘ 5” ,d 62v xix J -A ’d A VX flung X 3 D five 4'3: ‘16? 3 :9? 7’ 3 z 937‘ newly/7. 47H. a y Q. E1 i405” JL wad-x _[ 6. (10 points) Consider a square loop of wire} with resistance R, that lies in the :1: — y plane. It has sides of length L. Initially, a uniform magnetic field exists, with magnitude Bo and pointed in the 2 direction. Beginning at a certain point in time, which we’ll call t = 0, the magnetic field is caused to steadily decrease such that it reaches zero within one second. What is the EMF induced in the loop of wire at t = 0.5 seconds? 8 i3 6.. Lvuko“ 0;: 79 lap-Hanna. {:0 g‘ {7:} .flu-l' we. can. d¢$¢FCL¢ inf-Ha B(+) : {30(1.. 4:) duff-‘3 m4” ‘F‘Wt- so} A M «J .. A .. _ :43 L2 _-= in Bze) _ .. v A D 5%? Al A At B°O fig 8" .- -- __..._._._r 50.! {3&1 :7. B L2- 5 At; ° 7. (15 points) A toroid is made from a tightly wound solenoid that is bent into a torus, i.e., the shape of a donut. Prove that the magnetic field is zero everywhere outside the toroid. You must Show and explain all steps to get any credit. Wan!” A0 flu“; Pm {100 SICd'F‘S.‘ fifrfi' flu-w flu. gig am out? Fan/it “M awrfix‘w climatrml MUM 9W Mat {(-5 valua— WWflL !“ 'M-“ngfi’rm “ML Z“"“°~ Dipccfrt‘avt» 7A1 geomtrJ-m} 655;" MG. k:er [445 0~ Whit-twill gjmmd-f Roi-444% It 0500+ om (Ma's {rhea}.qu H‘s Cam/Ltqi‘r: in 4/!“ P/oww. 0‘; H01. [Do-439.. 60 H” CM? 1* obod?‘ [V's law/L1H :L‘Ag:s [fit/IEgM-‘j «Uri/£65k TIL¢FU¢¢UF¢ “flu; 'f' LG. W3ng OUBIIAQ. flz‘ fiQWtFJJ 0‘5 She-u)“ 4/111 finned/x 11:12,; {tho/L9H wt)th LL44”. VLo Git/LUMP SLLAPL Sfmffikmqou5ly gah‘s'py' *- cdgea‘ -">z(¢! (F on 4%; g/mwtcH/ am} 9 A K F. K Alfie-t fl { t‘ '47“ fl [#3 WV“? @figfs‘BL " Morédo %¢ ?'Amm {ML} L3 \ J, Nd :: Ext-(“o 6 B mm. a} PAM «Lady was” :3” B30 F “"3 554:3. W‘L A‘Elfiff Spa-cc???) fie Casi-1‘05 Bro/ (7'1; +FU¢ LU‘Jh/WLLLI“; Wfigla Mr. Jvrr‘ccir 8. (10 points) A laser is mounted as shown in the figure, a distance d from a converging lens, which has a positive focal length of f. The laser produces a light beam, with a wavelength of A} that travels parallel to the optical axis of the lens at a height b, above that axis. A large screen is placed a distance R to the right of the lens. The laser beam passes through the lens and makes a dot on the screen at a point that is a distance 3;, above the axis of the lens. Find 9 in terms of the variables given above. TA‘ 7234“! '70 in f' 15 wk“; farallchl was woulcl (31:65, 50 746“ ld—ns law-K415 714k“- 1‘9“— 9. (15 points) An object, mirror and thin lens are placed as shown below. The focal points of the lens are indicated. Show the ray tracing that is required to determine the final image location, and indicate that location. You need not calculate the position, just draw. a s f1 3 f1 5 Final Image —-> First Image —) ' ' 2nd Image —> 10. (15 points) Two radio antennas are located at points A and B? a dis- tance L apart. The antennas each radiate sinusoidal radio waves at a frequency f, but the signal transmission at antenna B is delayed in time relative to antenna A by a quarter of a period. A radio receiver is moved out from point B along a line perpendicular to the line connect~ ing A and B (i.e., moved along line BC shown in the figure). Determine a distance, 11:, away from B where there will be destructive interference. (Beware that the angles involved are not small enough to rely on small angle approximations.) _ W‘ ’// 5.3— cal¢5+ruc7l1ut t‘nhmflr an cm. a/ke. m. a. bait?" is M'Woufr 0-13 PM“. 4:“ Ma. Jam Saurccs (445») 47” #oz— Pea/d“, par-53,57... «avpflavxagm; 542'." “3‘7” #3: 11 7= ...
View Full Document

Page1 / 10

PHYS4final - Physics 4 Final, Saturday, March 22, 2008...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online