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several switches, and connecting wires. These components are to be used to
construct a hair dryer.
Schematics of Hair Dryer Components
F 110 V AC
Heating coil (two) Electric fan
Switch (several) The design requirements for your hair dryer are that the fan is always on when
the hair dryer is on and that it has two heat settings: high and low. Written Response — 15%
1. • Draw a schematic diagram of a hair dryer circuit that meets the design
requirements.
• Based on the circuit diagram you have drawn, analyze the operation of the hair
dryer. In your response, explain how the switch settings and their locations in the
circuit control the low and high heat settings. Also, explain why the hair dryer
should be designed so that the fan is on whenever the hair dryer is on. Note: Marks will be awarded for the physics principles used in your response and for the
effective communication of your response. 22 Writtenresponse question 2 begins on the next page.
23 Use the following information to answer the next question.
Several Canadian companies are redesigning and testing bulletproof vests.
One company does a test that involves firing a target rifle at a crash test
dummy wearing a vest. Dummy
Regular bullet mBullet = 8.00 g
vBullet = 650 m/s
Vest The company is testing the vests with both regular bullets and armourpiercing bullets. The armourpiercing bullet travels 1.20 times faster and
has 1.20 times the mass of the regular bullet shown above. Written Response — 15%
2. • Quantitatively compare the kinetic energy of the armourpiercing bullet with the
kinetic energy of the regular bullet.
• How much energy is released by the explosion of the gunpowder if the transfer of
energy from the explosion to the regular bullet is 90.0% efficient?
• The regular bullet is in the rifle barrel for 1.42 × 10–3 s. What is the average
force exerted on the regular bullet by the expanding gases? 24 Use this additional information to answer the next part of the question.
A second test performed by the company has the regular bullet strike the vest
at a glancing angle. The mass of the vest and the dummy is 56.0 kg. The
bullet–vest collision is inelastic. vBullet = 98.0 m/s mBullet = 8.00 g Path of bullet Vest 120°
Dummy vBullet = 650 m/s • Determine the resultant speed of the vest and the dummy following the glancing
collision shown above.
Clearly communicate your understanding of the physics principles that you
are using to solve this question. You may communicate this understanding
mathematically, graphically, and/or with written statements. 25 You have now completed the examination.
If you have time, you may wish to check your answers. 26 Fold and tear along perforation. PHYSICS DATA SHEET
CONSTANTS
Gravity, Electricity, and Magnetism Trigonometry and Vectors Acceleration Due to Gravity or
Gravitational Field Near Earth ............ ag or g = 9.81 m/s or 9.81 N/kg Gravitational Constant ........................ G = 6.67 × 10 Mass of Earth ...................................... Me = 5.98 × 10 kg Radius of Earth ................................... Re = 6.37 × 10 m Coulomb’s Law Constant.................... k = 8.99 × 10 N.m /C Electron Volt....................................... 1 eV = 1.60 × 10 Elementary Charge.............................. e = 1.60 × 10 Index of Refraction of Air................... n = 1.00 Speed of Light in Vacuum .................. c = 3.00 × 10 m/s 2 opposite
sin θ =
hypotenuse N.m /kg –11 2 2 24 2 –19 –19 R= adjacent
cosθ =
hypotenuse 6 9 For any Vector 2 tan θ = opposite
tan θ =
adjacent J 8 2 2 2 Ry
Rx Rx = R cos θ a
b
c
=
=
sin A
sin B
sin C C 2 Rx + Ry *
R Ry = R sin θ 2 c = a + b – 2ab cos C
Prefixes Used With SI Units Atomic Physics
Energy of an Electron in the 1st
Bohr Orbit of Hydrogen...................... E1 = – 2 .18 × 10 –18 Prefix J or –13.6 eV Symbol Exponential
Value Prefix Symbol Exponential
Value r1 = 5.29 × 10 Rydberg’s Constant for Hydrogen ...... m 7 eV.s –9 giga .............. G .................10 9 micro............ µ ..................10 RH = 1.10 × 10 /m –11 –15 12 –6 mega ............ M .................10 6 kilo .............. k ..................10 3 centi ............. c ..................10 Radius of 1st Bohr Orbit of Hydrogen –34 tera .............. T ..................10 –3 h = 6.63 × 10 pico .............. p...................10
nano ............. n...................10 J.s or 4.14 × 10 Planck’s Constant................................ –12 –2 hecto ............ h ..................10 2 deci .............. d...................10 –1 deka ............. da ................10 1 milli ............. m..................10
Particles
Rest Mass Charge Alpha Particle ............... mα = 6.65 × 10 –27 Electron......................... m e = 9.11 × 10 –31 Neutron ......................... m n = 1.67 × 10 –27 Proton........
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This note was uploaded on 01/14/2014 for the course PHYSICS Physics 30 taught by Professor Quinlan during the Fall '09 term at Centennial High School.
 Fall '09
 Quinlan
 Physics

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