5 20 5 n 1 2 3 so 30

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Unformatted text preview: e negative frequency components would not alias into the positive frequency components, the sampling frequency should meet the following conditions: −20!"# + 5!"# + ! ∗ !" < 20!"# − 5!"# (n = 1, 2, 3….) So: 30 !" < !"#(! = 1,2,3, !"# . ) ! Also, another condition the sampling frequency should meet with is: −20!"# − 5!"# + ! + 1 ∗ !" > 20!"# + 5!"#(! = 1,2,3, !"# . ) So: 50 !" > !"#(! = 1,2,3, !"# . ) !+1 To satisfy these two conditions, we can plot different positive integer n into the corresponding equations. After calculation, we can easily find out that only when n=1, the interval of Fs is meaningful. Therefore we can get: 25!"# < !" < 30!!" Therefore the lowest frequency at which the signal can be sampled without aliasing is 25MHz. 3. Answer: As from t...
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This note was uploaded on 01/13/2014 for the course EECS 452 taught by Professor Staff during the Fall '08 term at University of Michigan.

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