{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

EECS452_HW#1

# 5 20 5 n 1 2 3 so 30

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: e negative frequency components would not alias into the positive frequency components, the sampling frequency should meet the following conditions: −20!"# + 5!"# + ! ∗ !" < 20!"# − 5!"# (n = 1, 2, 3….) So: 30 !" < !"#(! = 1,2,3, !"# . ) ! Also, another condition the sampling frequency should meet with is: −20!"# − 5!"# + ! + 1 ∗ !" > 20!"# + 5!"#(! = 1,2,3, !"# . ) So: 50 !" > !"#(! = 1,2,3, !"# . ) !+1 To satisfy these two conditions, we can plot different positive integer n into the corresponding equations. After calculation, we can easily find out that only when n=1, the interval of Fs is meaningful. Therefore we can get: 25!"# < !" < 30!!" Therefore the lowest frequency at which the signal can be sampled without aliasing is 25MHz. 3. Answer: As from t...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online