35 kg i s pl aced on top of the spr i ng and the

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Unformatted text preview: mass m = 2.35 kg i s pl aced on top of the spr i ng and the system i s at r est? cm www.we ba ssign.ne t/we b/Stude nt/Assignme nt- Re sponse s/la st? de p= 5966130 1/5 6/13/13 HW 16 3. –/1 points S e rCP 9 13.P .005.soln. A spr i ng i s hung f r om a cei l i ng, and an object attached to i ts l ower end str etches the spr i ng by a di stance d = 7.80 cm f r om i ts unstr etched posi ti on when the system i s i n equi l i br i um as i n the f i gur e bel ow. If the spr i ng constant i s 50.5 N/m, deter mi ne the mass of the object. kg 4. –/3 points S e rCP 9 13.P .007. A spr i ng 1.50 m l ong wi th f or ce constant 461 N/m i s hung f r om the cei l i ng of an el evator , and a bl ock of mass 11.7 kg i s attached to the bottom of the spr i ng. (a) By how much i s the spr i ng str etched when the bl ock i s sl owl y l ower ed to i ts equi l i br i um poi nt? m (b) If the el evator subsequentl y accel er ates upwar d at 1.90 m/s2, what i s the posi ti on of the bl ock, taki ng the equi l i br i um posi ti on f ound i n par t (a) as y = 0 and upwar ds as the posi ti ve y­di r ecti on. m (c...
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This document was uploaded on 01/13/2014.

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