2W04 Assignment 6 -2009 Solutions

10kwh 1350year airconda

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: / COPB ) = (120,000 kWh/year)(1/3.2 − 1 / 5.0) = 13,500 kWh/year Cost savings = (Energy savings)( Unit cost of energy) = (13,500 kWh/year)($0.10/kWh) = $1350/year Air Cond. A The installation cost difference between the two air‐conditioners is Air Cond. B Cost difference = Cost of B – cost of A = 7000 – 5500 = $1500 Therefore, the more efficient air‐conditioner B will pay for the $1500 cost differential in this case in about 1 year. Discussion A cost conscious consumer will have no difficulty in deciding that th...
View Full Document

This note was uploaded on 01/17/2014 for the course MECH ENG 2w04 taught by Professor Cotton during the Winter '13 term at McMaster University.

Ask a homework question - tutors are online