2W04 Assignment 6 -2009 Solutions

37 5952 kjmin 4982 kjmin

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Unformatted text preview: − = 0.744 1173 K TH 900°C ‐5°C Then the maximum power output of this heat engine is 800 kJ/min determined from the definition of thermal efficiency to be HE & & Wnet,out = η th QH = (0.744)(800 kJ/min ) = 595.2 kJ/min R 27°C & which is also the power input to the refrigerator, Wnet,in . The rate of heat removal from the refrigerated space will be a maximum if a Carn...
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