This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: MAT 33 Fall 2007 Homework #7 Solutions Due: 10/29/07 1.) For a brass alloy under tension, the following engineering stresses produce the corresponding plastic engineering strains, prior to necking. Engineering Stress (MPa) Engineering Strain 315 0.105 340 0.220 (i) Calculate the true stress, T and true strain and T for both of these loading situations (ii) The true stress and true strain are related by T = K T n . Calculate the strain hardening exponent, n, and the constant K for this material. (iii) Calculate the engineering stress necessary to produce an engineering strain of 0.28 in this material. (i) Since T = (1 + ) then T 1 = (315 MPa)(1 + 0.105)= 348 MPa T 2 = (340 MPa)(1 + 0.220)= 415 MPa Similarly for strains, since T = ln(1 + ) then T 1 = ln (1 + 0.105)= 0.09985 T 2 = ln (1 + 0.220)= 0.19885 (ii) Taking logarithms of T = K T n we get log T = log K + n log T which allows us to set up two simultaneous equations for the above pairs of true stresses and true strains, with K and n as unknowns. Thus log (348) = log K + n log (0.09985)log (348) = log K + n log (0....
View Full Document
- Fall '07