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Unformatted text preview: 980 N Rem = ρVc/µ = (1.225kg/m3)(50 m/s)(0.10m)/(1.78×10‐5 kg/m∙s) = 340,000 Ref‐s = ρVc/µ = (1.225kg/m3)(50 m/s)(1.00m)/(1.78×10‐5 kg/m∙s) = 3,400,000 V = Reµ/ρc = (3,400,000)(1.78×10‐5 kg/m∙s)/{( 1.225kg/m3)(0.100m)} = 500 m/s Note: Mf‐s = (50m/s)/347m/s) = 0.14 (at seal level, standard conditions) (subsonic) Mm = (500m/s)/347m/s) = 1.44 which is a very different situation (supersonic, with shock waves) It is difficult to match both Re and Mach exactly Today we finish chapter 1. Chapter 2 gets pretty mathematical, we will have two or three pretty heavy math days For Wed read 2.1‐2.3, 2.9 For Friday read 2.4‐2.9 For Monday read 2.10‐2.11 For Wed read 2.14‐2‐16 Our first exam will cover chapters 1 and 2. Types of flo...
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This note was uploaded on 01/19/2014 for the course AEEM 2042C taught by Professor Munday during the Fall '10 term at University of Cincinnati.

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