ENGM3052
Fall 1999
Assignment #6: Solutions
1) The program
ntddm
consists of
mntddm.f
,
ntddm.f
, and
polydd.f
(or
.c
for C pro
grammers). The results of this program when run on
a6q1a.dat
and
a6q1b.dat
are as
follows, respectively,
Radon Test Data Along Sites 11 through 15
Polynomial Coefficients = 13.0000,
1.5000, 0.5000,
0.1313, 0.0318
Estimate of f( 3.60) =
10.9580803
Radon Test Data Along Sites 3, 8, 13, 18, and 23
Polynomial Coefficients = 13.3000,
0.5500,
0.0125, 0.0125, 0.0005
Estimate of f( 4.40) =
10.7972803
The data along sites 11 through 15 thus suggest that the radon concentration at the house is
17.4 ppm, while the data along sites 3 through 23 suggest a concentration of 20.46 ppm. So
we’re still on the fence here. Probably best to get a test done at the house (or recognize that
the 20 ppm is possibly arbitrarily set in itself and do a little research to find out just how the
health risk varies with concentration).
2) Using
(
) =
5
=1
=
we get
1
(
) =
2
0
2
4
0
4
6
0
6
8
0
8
=
1
384
(
2)(
4)(
6)(
8)
2
(
) =
0
2
0
4
2
4
6
2
6
8
2
8
=
1
96
(
)(
4)(
6)(
8)
3
(
) =
0
4
0
2
4
2
6
4
6
8
4
8
=
1
64
(
)(
2)(
6)(
8)
4
(
) =
0
6
0
2
6
2
4
6
4
8
6
8
=
1
96
(
)(
2)(
4)(
8)
5
(
) =
0
8
0
2
8
2
4
8
4
6
8
6
=
1
384
(
)(
2)(
4)(
6)
so that
4
(
) =
13
1
(
) + 10
2
(
)
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 Fall '09
 Fenton
 Polynomial interpolation, Spline interpolation, Cubic Hermite spline, Radon Test Data

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