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Assignment 6 Solution

Assignment 6 Solution - ENGM3052 Fall 1999 Assignment#6...

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ENGM3052 Fall 1999 Assignment #6: Solutions 1) The program ntddm consists of mntddm.f , ntddm.f , and polydd.f (or .c for C pro- grammers). The results of this program when run on a6q1a.dat and a6q1b.dat are as follows, respectively, Radon Test Data Along Sites 11 through 15 Polynomial Coefficients = -13.0000, 1.5000, -0.5000, 0.1313, -0.0318 Estimate of f( 3.60) = -10.9580803 Radon Test Data Along Sites 3, 8, 13, 18, and 23 Polynomial Coefficients = -13.3000, 0.5500, 0.0125, -0.0125, -0.0005 Estimate of f( 4.40) = -10.7972803 The data along sites 11 through 15 thus suggest that the radon concentration at the house is 17.4 ppm, while the data along sites 3 through 23 suggest a concentration of 20.46 ppm. So we’re still on the fence here. Probably best to get a test done at the house (or recognize that the 20 ppm is possibly arbitrarily set in itself and do a little research to find out just how the health risk varies with concentration). 2) Using ( ) = 5 =1 = we get 1 ( ) = 2 0 2 4 0 4 6 0 6 8 0 8 = 1 384 ( 2)( 4)( 6)( 8) 2 ( ) = 0 2 0 4 2 4 6 2 6 8 2 8 = 1 96 ( )( 4)( 6)( 8) 3 ( ) = 0 4 0 2 4 2 6 4 6 8 4 8 = 1 64 ( )( 2)( 6)( 8) 4 ( ) = 0 6 0 2 6 2 4 6 4 8 6 8 = 1 96 ( )( 2)( 4)( 8) 5 ( ) = 0 8 0 2 8 2 4 8 4 6 8 6 = 1 384 ( )( 2)( 4)( 6) so that 4 ( ) = 13 1 ( ) + 10 2 ( )
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