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Unformatted text preview: pper triangular, which implies that M is normal. Since M is
upper triangular and normal, we know that it is diagonal. Since the eigenvalues of R2 R1 1 are
strictly positive and have magnitude 1, we know that R2 R1 1 = I = Q∗ Q1 . Thus, R2 = R1 and
Q2 = Q1 . Hence, the factorization is unique. \\
Use Gram Schmidt. We assume A is invertible, so its column vectors are linearly independent. We
can form an orthonormal basis. Let A = [a1 a2 · · · an ]. We form the orthonormal ba...
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