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g fn x p n x 2k 2n
an d the length of each such in terval is
k ways to have k heads is E e D2 n k 1
22 n k 22 n 2n
k0 k 2 , so that 2n
n . Each bar is of width 2n g 2k 2n 1 2n 22 n k0 2n
2n g 2k 2n 2n ....
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This note was uploaded on 01/19/2014 for the course MATH 5002 taught by Professor Adams during the Spring '08 term at Minnesota.
- Spring '08