FM5002-HW10-4.18.12 (1)

For the kth bar n 2n x 1 2n an d p n x g fn x p n x 2

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Unformatted text preview: the right g fn x p n x 2k 2n an d the length of each such in terval is k ways to have k heads is E e D2 n k 1 22 n k 22 n 2n k0 k 2 , so that 2n 2 2n n . Each bar is of width 2n g 2k 2n 1 2n 22 n k0 2n k 2 2n g 2k 2n 2n ....
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This note was uploaded on 01/19/2014 for the course MATH 5002 taught by Professor Adams during the Spring '08 term at Minnesota.

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