3a forward active region 3b inverted

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Unformatted text preview: nt, I E Solution: I E = I En + I Ep = 2.00 + 0.01 = 2.01 I E = 2.01 mA 2d) Determine ! DC . Solution: ! DC = " ! T = 0.995 # 0.99 = 0.985 ! DC = 0.985 2e) Determine ! DC . Solution: ! DC = ECE ­606 " DC 0.985 = = 65.9 1 # " DC 1 # 0.985 ! DC = 65.9 3 Spring 2013 Exam 4: ECE 606 3) Spring 2013 Sketch the minority hole concentration in the base of a PNP BJT for the following conditions. In each case, indicate the magnitude of !p at x = xn and at x = xn + WB . 3a) Forward active region. 3b) Inverted active region....
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This note was uploaded on 01/15/2014 for the course ECE 606 taught by Professor Staff during the Fall '08 term at Purdue University-West Lafayette.

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