Week1HWSolutions

49 100 201 101 022 n n mb f 1 2 3 exp 3

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Unformatted text preview: × 10−5 = 1 M nL nL B = F −1/ 2 ( −10 ) exp ( −10 ) = 1 n n MB = F +1/ 2 (η F ) exp (η F ) = F +1/ 2 ( −10 ) exp ( −10 ) = 4.54 × 10−5 4.54 × 10−5 = 1 ECE- 656 n n MB = F +1/ 2 ( −10 ) exp (10 ) = 1 4 Fall 2013 Mark Lundstrom 8/24/2013 ECE 656 Homework 1: Week 1 (continued) b) eta_F = - 3: M nL nL B = F −1/ 2 (η F ) exp (η F ) = F −1/ 2 ( −3) exp ( −3) = 4.81 × 10−2 4.98 × 10−2 = 0.97 M nL nL B = F −1/ 2 ( −3) exp ( −3) = 0.97 n n MB = F +1/ 2 (η F ) exp (η F ) = F +1/ 2 ( −3) exp ( −3) = 4.89 × 10−2 4.98 × 10−2 = 0.98 n n MB = F +1/ 2 ( −3) exp ( −3) = 0.98 c) eta_F = 0: M nL nL B = F −1/ 2 (η F ) exp (η F ) = F −1/ 2 ( 0 ) exp ( 0 ) = 6.05 × 10−1 1 = 0.61 M nL nL B = F −1/ 2 ( −3) exp ( −3) = 0.61 n n MB = F +1/ 2 (η F ) exp (η F ) = F +1/ 2 ( 0 ) exp ( 0 ) = 7.65 × 10−1 1 = 0.77 n n MB = F +1/ 2 ( −3) exp ( −3) = 0.77 d) eta_F = +3: M nL nL B = F −1/ 2 (η F ) exp (η F ) = F −1/ 2 ( 3) exp ( 3) = 1.85 × 100 2.01 × 101 = 0.092 M nL nL B = F −1/ 2 ( 3) exp ( 3) = 0.092 n n MB = F +1/ 2 (η F ) exp (η F ) = F +1/ 2 ( 3) exp ( 3) = 4.49 × 100 2.01 × 101 = 0.22 n n MB = F +1/ 2 ( −3) exp ( −3) = 0.22 ECE- 656 5 Fall 2013 Mark Lundstrom 8/24/2013 ECE 656 Homework 1: Week 1 (continued) e) eta_F...
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This document was uploaded on 01/15/2014.

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