Homework2_solutions

Homework2_solutions - 2 ) 2 = 60 o (1 0 0) (110) Area = a x...

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MAT 33 – Fall 2003 Homework #2 Due: 09/08/03 1.) Draw the following direction vectors in a cubic unit cell: (a) [100] and [110] (b) [112], (c) [10], (d) [2] 2.) Draw the following crystallographic planes in a cubic unit cell: (a) (101), (b) (10), (c) (221)
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3.) Draw a (110) plane in a BCC atomic site unit cell, and list the position coordinates of the atoms whose centers are intersected by this plane. 4 .) Calculate and compare the planar densities of the (100) and (110) planes for a BCC unit cell. The (110) planar density is the larger than the (100) planar density by a factor of 2 . NB. The result can also be expressed in terms of atomic radius since 4R = 3 a for BCC. 5.) What is the angle between the [110] and the [011] directions in a cubic system? Use vector dot product. Cos θ = [110].[011] / (
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Unformatted text preview: 2 ) 2 = 60 o (1 0 0) (110) Area = a x a = a 2 No of atoms = x 4 = 1 Planar density = 1/a 2 Area = a x a = a 2 No of atoms = ( x 4) + 1 = 2 Planar density = 2/a 2 = /a 2 Atoms at (1,0,0) (0,1,0) (1,0,1) (0,1,1) ( , , ) 6.) Calculate the radius of an iridium atom, given that Ir has an FCC crystal structure, a density of 22.4g/cm 3 , and an atomic weight of 192.2 gmol-1 . For FCC, n = 4 atoms/unit cell, and V C = 16 R 3 2 . Now, = nA Ir V C N A And solving for R from the above two expressions yields R = nA Ir 16 N A 2 1/3 = 4 atoms/unit cell ( 29 192.2 g/mol ( 29 2 ( 29 16 ( 29 22.4 g/cm 3 ( 29 6.023 x 10 23 atoms/mol ( 29 1/3 = 1.36 x 10-8 cm = 0.136 nm...
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Homework2_solutions - 2 ) 2 = 60 o (1 0 0) (110) Area = a x...

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