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Homework 3 Solutions - Fall 2013 Homework#3 Solutions...

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Fall 2013 Homework #3 Solutions Problem 1 Graded individually Sample answer: the total available green time is split between the phases by first calculating the effective green time split (g i ) for each phase. To calculate the effective green time for each phase (g T ), you need to multiply the total effective green time by the phase flow ratio over the total flow ratio. You can then compute the green time (G i ). Calculations: Problem 2 Point Distribution 0.5 points each = N/S;E/W Yellow Time t = 1.2 s V 85 = 45mph 30mph a = 10 ft/sec 2 G = 32.2 ft/sec 2 g = 0% All-Red Time w = 58ft; 68ft L = 20ft P = 62ft; 74ft V 15 = 35mph (51.45); 20mph (36.75) Max(~,~) A: First, we will look at the N-S direction, yellow time. ( ) ( ) Next will be the N-S All-Red Time (clearance interval) [ ( ) ] [ ] [ ] We will now calculate the E-W direction yellow and all-red times.
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( ) ( ) [ ( ) ] [ ] [ ] Problem 3 (15 pts.) For (a) Two Phases: Three Phases: Four Phases:
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Part (b) and (c), Two Phase: Direction EB LT WB LT EB T WB T NB LT SB LT NB T SB T Original Volumes 283 287 554 502 115 108 495/2 Lanes 528/2 Lanes Modified Volumes (3.0LT and .9 PHF) 943 957
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