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How many workers produced less than 23 tools solution

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Unformatted text preview: s? 2. How many workers produced less than 23 tools? Solution: Using sturges formula for determining the number of class intervals, we have Number of class intervals = 1+ 3.322 log10N = 1+ 3.322 log10100 = 7.6 Sizes of class interval = Range Number of class interval 46 - 13 7.6 5 Hence taking the magnitude of class intervals as 5, we have 7 classes 13-17, 18-22… 43-47 are the classes by inclusive type. Using tally marks, the required frequency distribution is obtain in the following table = 58 Class Interval Tally Marks 13-17 18-22 23-27 28-32 33-37 38-42 43-47 Total Number of tools produced (Frequency) 6 11 18 25 22 11 7 100 4.7 Percentage frequency table: The comparison becomes difficult and at times impossible when the total number of items are large and highly different one distribution to other. Under these circumstances percentage frequency distribution facilitates easy comparability. In percentage frequency table, we have to convert the actual frequencies into percentages. The percentages are calculated by using the formula given below: Actual Frequency Frequency percentage = × 100 Total Frequency It is also called relative frequency table: An example is given below to construct a percentage frequency table. Marks 0-10 10-20 20-30 30-40 40-50 50-60 Total No. of students 3 8 12 17 6 4 50 59 Frequency percentage 6 16 24 34 12 8 100 4.8 Cumulative frequency table: Cumulative frequency distribution has a running total of the values. It is constructed by adding the frequency of the first class interval to the frequency of the second class interval. Again add that total to the frequency in the third class interval continuing until the final total appearing opposite to the last class interval will be the total of all frequencies. The cumulative frequency may be downward or upward. A downward cumulation results in a list presenting the number of frequencies “less than” any given amount as revealed by the lower limit of succeeding class interval and the upward cumulative results in a list presenting the number of frequencies “more than” and given amount is revealed by the upper limit of a preceding class...
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