HW-04 Solutions - Problem 4.68 Given Water flowing past cylinder Find[Difficulty 2 Horizontal force on cylinder V y x Solution CS Rx Basic equation

HW-04 Solutions - Problem 4.68 Given Water flowing past...

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Problem 4.68 [Difficulty: 2] CS c R x d V V θ y x Given: Water flowing past cylinder Find: Horizontal force on cylinder Solution: Basic equation: Momentum flux in x direction Assumptions: 1) Steady flow 2) Incompressible flow 3) Atmospheric pressure throughout 4) Uniform flow Hence R x u 1 ρ u 1 A 1 ( ) u 2 ρ u 2 A 2 ( ) + = 0 ρ V sin θ ( ) ( ) V a b ( ) + = R x ρ V 2 a b sin θ ( ) = For given data R x 1000 kg m 3 3 m s 2 × 0.0125 × m 0.0025 × m sin 20 deg ( ) × N s 2 kg m × = R x 0.0962 N = This is the force on the fluid (it is to the left). Hence the force on the cylinder is R x R x = R x 0.0962 N =
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Problem 4.75 [ Difficulty: 2]
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Problem 4.83 [ Difficulty: 2]
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Problem 4.88 [ Difficulty: 3]
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