The speed is then given by 101 20 sin t the speed is

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: , −3� = 6 − 6 = 0, the line is parallel to the plane. Problem 3. a) �B � O � � � A − − → − → OA = �10t, 0� and AB = �cos t, sin t�, hence −→ − − →− − → OB = OA + AB = �10t + cos t, sin t�. The rear bumper is reached at time t = π and the position of B is (10π −1, 0). → − b) V = �10 − sin t, cos t�, thus → − | V |2 = (10 − sin t)2 + cos2 t = 100 − 20 sin t + sin2 t + cos2 t = 101 − 20 sin t. √ The speed is then given by 101 − 20 sin t....
View Full Document

This note was uploaded on 01/21/2014 for the course MATH 18.02C taught by Professor Denisauroux during the Fall '12 term at MIT.

Ask a homework question - tutors are online