prac exam 2B solutions

Hence s f n ds x2 y 2 1 y x z y x 1 dx dy 2 1 x2

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Unformatted text preview: s φ and x2 +y 2 +z 2 = ρ2 , so ρ cos φ = ρ4 . This simplifies to cos φ = ρ3 , or ρ = (cos φ)1/3 . (cos φ)1/3 π /2 2π c) 0 0 ρ2 sin φ dρ dφ dθ. 0 9. The flux is calculated upwards through the graph of z = f (x, y ) = xy , so ˆ n dS = −fx...
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