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Unformatted text preview: uares regression equation,
predicted value of Y when X = 3.25?
A. 15.42
B. 15.61
C. 27.78
D. 44.92 = 12.36 + 4.745(X), and determine the = 12.36 + 4.745(3.25) = 27.78 AACSB: Analytic
Bloom's: Application
Difficulty: Easy
Learning Objective: 1
Topic: Simple Linear Regression 127. Consider the following partial computer output from a simple linear regression analysis. What is the estimated yintercept?
A. 1.12
B. 28.13
C. 22.90
D. .99 AACSB: Analytic
Bloom's: Application
Difficulty: Easy
Learning Objective: 4
Topic: Simple Linear Regression 11280 Chapter 01  An Introduction to Business Statistics 128. Consider the following partial computer output from a simple linear regression analysis. What is the estimated slope?
A. 1.12
B. 28.13
C. 22.90
D. .05 AACSB: Analytic
Bloom's: Application
Difficulty: Easy
Learning Objective: 4
Topic: Simple Linear Regression 129. Consider the following partial computer output from a simple linear regression analysis. Write the equation of the least squares line.
A. ŷ = 1.12  28.13x
B. ŷ = 28.13 + 1.12
C. ŷ = 28.13 + 1.12x
D. ŷ = 1.12 + .04891x AACSB: Analytic
Bloom's: Application
Difficulty: Easy
Learning Objective: 4
Topic: Simple Linear Regression 11281 Chapter 01  An Introduction to Business Statistics 130. Consider the following partial computer output from a simple linear regression analysis. Test H0: β1 ≤ 0 vs. Ha: β1 > 0.
A. .088, fail to reject null hypothesis
B. 22.895, reject the null hypothesis
C. .088, reject the null hypothesis
D. 22.895, fail to reject the null hypothesis
.0001 < .05, reject H0 AACSB: Analytic
Bloom's: Application
Difficulty: Medium
Learning Objective: 4
Topic: Significance of the slope 131. Consider the following partial computer output from a simple linear regression analysis. What is the predicted value of y when x = 1,000?
A. 1148.13
B. 27.01
C. 1091.87
D. 1142.90
= 28.13 + 1.12(1000) = 1091.87 AACSB: Analytic
Bloom's: Application
Difficulty: Easy
Learning Objective: 4
Topic: Simple Linear Regression 11282 Chapter 01  An Introduction to Business Statistics 132. Consider the following partial computer output from a simple linear regression analysis. Calculate the correlation coefficient.
A. .9722
B. .986
C. .088
D. .2968 AACSB: Analytic
Bloom's: Application
Difficulty: Medium
Learning Objective: 6
Topic: Correlation 11283 Chapter 01  An Introduction to Business Statistics 133. Complete the following partial ANOVA table from a simple linear regression analysis
with a sample size of 16 observations. Find the F test to test the significance of the model. A. 3.214
B. 6.78
C. 6.33
D. 4.60
F = 6.33, reject H0 F.05,1,14 = 4.60
6.33 > 4.60, reject H0. AACSB: Analytic
Bloom's: Application
Difficulty: Hard
Learning Objective: 8
Topic: F test 11284 Chapter 01  An Introduction to Business Statistics 134. Consider the following partial computer output from a simple linear regression analysis
with a sample size of 16 observations. Find the t test to test the significance of the model. A. 2.52
B. 2.61
C. 2.15
D. 2.65
t = 2.52, reject H0 AACSB: Analytic
Bloom's: Application
Difficulty: Medium
Learning Objective: 4
Topic: Significance of the slope 11285 Chapter 01  An Introduction to Business Statistics 135. Consider the following partial computer output from a simple linear regression analysis. S = 0.4862 RSq = ______
Analysis of Variance What is the estimated yintercept?
A. 4.862
B. 0.347
C. .5201
D. .8089 AACSB: Analytic
Bloom's: Application
Difficulty: Medium
Learning Objective: 4
Topic: Simple Linear Regression 11286 Chapter 01  An Introduction to Business Statistics 136. Consider the following partial computer output from a simple linear regression analysis. S = 0.4862 RSq = ______
Analysis of Variance What is the estimated slope?
A. 4.862
B. 0.347
C. .5201
D. .05866 AACSB: Analytic
Bloom's: Application
Difficulty: Medium
Learning Objective: 4
Topic: Simple Linear Regression 11287 Chapter 01  An Introduction to Business Statistics 137. Consider the following partial computer output from a simple linear regression analysis. S = 0.4862 RSq = ______
Analysis of Variance Write the equation of the least squares line.
A. y = 4.8615 + 0.34655x
B. y = .34655 + 4.8615x
C. y = 4.8615  .34655x
D. y = .5201 + .05866x
y = 4.8615 0.34655 x AACSB: Analytic
Bloom's: Application
Difficulty: Easy
Learning Objective: 1
Topic: Simple Linear Regression 11288 Chapter 01  An Introduction to Business Statistics 138. Consider the following partial computer output from a simple linear regression analysis. S = 0.4862 RSq = ______
Analysis of Variance Test H0:
= .001. What do you conclude about the
1 = 0 versus Ha:
1 ≠ 0 by setting
relationship between y and x?
A. Reject the null hypothesis, significant linear relationship between x and y
B. Fail to reject the null hypothesis, no evidence of a linear relationship between x and y
0.34655/0.05866 = 5.908 compared to t statistic of 4.221 (for = .001, df = 13) so reject
the null hypothesis at .001. There i...
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This document was uploaded on 01/20/2014.
 Winter '14

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