1-20chapter stats

Method 1 is a traditional method of training and

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Unformatted text preview: of 1000 adults from the U.S.A and 1000 adults from Germany were asked whether they supported the death penalty. 590 American adults and 560 German adults indicated that they supported the death penalty. The researcher wants to know if there is sufficient evidence to conclude that the proportion of adults who support the death penalty is higher in the U.S.A. than in Germany. What is the decision at = .10? A. Reject the null hypothesis B. Can't reject the null hypothesis 112. In an opinion survey, a random sample of 1000 adults from the U.S.A and 1000 adults from Germany were asked whether they supported the death penalty. 590 American adults and 560 German adults indicated that they supported the death penalty. The researcher wants to know if there is sufficient evidence to conclude that the proportion of adults who support the death penalty is higher in the U.S.A. than in Germany. What is the decision at = .05? A. Reject the null hypothesis B. Can't reject the null hypothesis 113. In an opinion survey, a random sample of 1000 adults from the U.S.A and 1000 adults from Germany were asked whether they supported the death penalty. 590 American adults and 560 German adults indicated that they supported the death penalty. The researcher wants to know if there is sufficient evidence to conclude that the proportion of adults who support the death penalty is higher in the U.S.A. than in Germany. What is the p-value for this test? A. 0.003 B. 0.1738 C. 0.0869 D. 0.0274 114. Find a 95 percent confidence interval for the difference between the proportions of people who prefer cola versus root beer (RB) where 150. A. (-0.018 0.198) B. (0.0255 0.1545) C. (0.073 0.107) D. (0.013 0.167) 1-847 cola = .21, = .12, ncola = 200, nRB = RB Chapter 01 - An Introduction to Business Statistics 115. The mid-distance running coach, Zdravko Popovich, for the Olympic team of an eastern European country claims that his six-month training program significantly reduces the average time to complete a 1500-meter run. Five mid-distance runners were randomly selected before they were trained with coach Popovich's six-month training program and their completion time of 1500-meter run was recorded (in minutes). After six months of training under coach Popovich, the same five runners' 1500 meter run time was recorded again the results are given below. At an alpha level of .05, can we conclude that there has been a significant decrease in the mean time per mile? A. Reject the null hypothesis B. Can't reject the null hypothesis 116. The mid-distance running coach, Zdravko Popovich, for the Olympic team of an eastern European country claims that his six-month training program significantly reduces the average time to complete a 1500-meter run. Five mid-distance runners were randomly selected before they were trained with coach Popovich's six-month training program and their completion time of 1500-meter run was recorded (in minutes). After six months of training under coach Popovich, the same five runners' 1500 meter run time was recorded again the results are given below. Construct the appropriate 95% confidence interval. (sd = .228) A. (0.063 0.497) B. (-0.206 0.766) C. (-0.003 0.563) D. (0.018 0.542) 1-848 Chapter 01 - An Introduction to Business Statistics 117. A marketing research company surveyed grocery shoppers in the east and west coasts to see the percentage of the customers who prefer chicken to other meat. The data are given below. Is the proportion of customers who prefer chicken the same for the two regions? Test at α = . 10. A. Reject the null hypothesis B. Can't reject the null hypothesis 118. A marketing research company surveyed grocery shoppers in the east and west coasts to see the percentage of the customers who prefer chicken to other meat. The data are given below. Is the proportion of customers who prefer chicken higher at the West Coast? Test at 05. A. Reject H0 B. Fail to reject H0 1-849 =. Chapter 01 - An Introduction to Business Statistics 119. A marketing research company surveyed grocery shoppers in the east and west coasts to see the percentage of the customers who prefer chicken to other meat. The data are given below. What is the test statistic for this hypothesis test? A. 1.645 B. 3.92 C. 1.96 D. 3.09 120. A marketing research company surveyed grocery shoppers in the east and west coasts to see the percentage of the customers who prefer chicken to other meat. The data are given below. Determine the 95% confidence interval for the difference between the proportion of customers who prefer chicken at the West Coast and the proportion of customers who prefer chicken at the East Coast. A. (0.075 0.183) B. (0.044 0.213) C. (0.096 0.161) D. (0.064 0.193) 1-850 Chapter 01 - An Introduction to Business Statistics 121. Two hospital emergency rooms use different procedures for triage of their patients. We want to test the claim that the mean waiting time of patients is the same for both hospitals. The 40 randomly selected subjects...
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