Assume that the equation for cell growth is s p maz

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Unformatted text preview: eving this conversion is through isomerization of xylose to xylulose, and transformation of xylulose to hexose, and hexose to ethanol by yeast, as shown by k A 1 S k‒1 S y east P where A = xylose (a pentose), S = xylulose (also a pentose), and P = ethanol (the product). Assume that the equation for cell growth is ⎛ྎ µ S ⎞ྏ⎛ྎ P ⎞ྏ µ = ⎜ྎ maz ⎟ྏ⎜ྎ1 − ⎜ྎ K + S ⎟ྏ⎜ྎ P ⎟ྏ ⎟ྏ max ⎠ྏ ⎝ྎ s ⎠ྏ⎝ྎ n The yield coefficients...
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This note was uploaded on 01/20/2014 for the course CHE 489 taught by Professor Wang during the Spring '10 term at USC.

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