Discussion Quiz 3 Solution

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Unformatted text preview: the total charge contained within the Gaussian surface, but in this case, it is just the charge contained by the object (the charge density stops at the actual geometry of the charge, and not at the Gaussian surface which is something you make up). In this case, the integration extends to the edge of the actual object. However, when the point of interest is inside the charge distribution, then you must stop the integration at the outer edge of the Gaussian surface, NOT the outer edge of the actual object. Take a look at the example in your textbook 22.9 Gauss’s Law requires that you figure out the entire charge contained within the Gaussian surface so if there are two objects (like a solid insulator within a spherical shell), the for points outside of both, then the total charge is the charge contained by both objects. If one is...
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