Discussion Quiz 6 Solution

# It is surrounded by a hollow conducting cylinder of

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Unformatted text preview: /ε0. You must find the electric potential to find the capacitance ) 2) Find the equivalent capacitance of the above configuration. If the voltage across C1 is 3V, find the charge on C1 and C4. 1) From Gauss’s Law, the electric field is E = λ/2πε0r So the electric potential difference between the surfaces (r = a and r = b) is V =(λ/2πε0)ln(b/a) Going back to the definition of capacitance C = Q/V We plug in the voltage to get C = 2πε0L/ln(b/a) 2) Remembering the rules for adding capacitors: Series: C23 = (1/C2 + 1/C3)^- 1 = C2C3/(C2+C3) Parallel: Cnet = C1 + C23 + C4 = C1 + C4 + C2C3/(C2+C3) To find the charge on C1, we go back to the definition of capacitance. C = Q/V → Q = VC So the charge on each capacitor is just Q1 = 3VC1 Q2 = 3VC2...
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## This note was uploaded on 01/22/2014 for the course PHYS 7D taught by Professor Barwick during the Spring '12 term at UC Irvine.

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