{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

This preview shows pages 1–3. Sign up to view the full content.

HW#7 Answer Key 7.1) Sedimentation coefficient, s=v/ ω 2 r If angular velocity is doubled, 2 ω , note that v depends on ω 2 such that v= 4v. Then s= 4v/4 ω 2 r= v/ ω 2 r, so s remains unchanged . This result agrees with sedimentation coefficients being constant properties of molecules, depending on their molecular properties (m, φ , ω , f) and not on experimental parameters. 7.2) s = where φ =density increment= 1 v protein p solvent = 1 (0.75cm 3 /g)*(1.0g/cm 3 )=0.25 And f= 6 πη r=6 π *0.010 g/cm s* =6 π *0.010 g/cm s* =2.73x10 7 g/s Then, s= = = 1.52x10 11 s= 152 Svedbergs 7.3) = = 43375.1 g/mol = 43.4 kD 7.4) 2A B A) reaction velocity v= = = 0.0025 M/s B) For second order recation in A, v= = k[A] 2 which is rearranged as = 2kdt. Integrate both sides, get the 2 nd order rate law in terms of [A]:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}