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HWK7_answer_key

HWK7_answer_key - HW#7AnswerKey 7.1),s=v/2r ,2, v=...

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HW#7 Answer Key 7.1) Sedimentation coefficient, s=v/ ω 2 r If angular velocity is doubled, 2 ω , note that v depends on ω 2 such that v= 4v. Then s= 4v/4 ω 2 r= v/ ω 2 r, so s remains unchanged . This result agrees with sedimentation coefficients being constant properties of molecules, depending on their molecular properties (m, φ , ω , f) and not on experimental parameters. 7.2) s = where φ =density increment= 1 v protein p solvent = 1 (0.75cm 3 /g)*(1.0g/cm 3 )=0.25 And f= 6 πη r=6 π *0.010 g/cm s* =6 π *0.010 g/cm s* =2.73x10 7 g/s Then, s= = = 1.52x10 11 s= 152 Svedbergs 7.3) = = 43375.1 g/mol = 43.4 kD 7.4) 2A B A) reaction velocity v= = = 0.0025 M/s B) For second order recation in A, v= = k[A] 2 which is rearranged as = 2kdt. Integrate both sides, get the 2 nd order rate law in terms of [A]:
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HWK7_answer_key - HW#7AnswerKey 7.1),s=v/2r ,2, v=...

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