{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Midterm Solutions 5

Hence 2 1 167 kpa 2 185 kpa

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: mol ⎞ π 1 = (1) ⎜ 10 ⎟ ( 0.75 ) ⎜ 0.082 ⎟ ( 298 K ) ⎜ ⎝ ⎝ ⎝ 1000 mmol ⎟ ⎠ L⎠ mol-K ⎠ π 1 = 0.183 atm Since 101.3 kPa is equal to 1 atm, the osmotic pressure is approximately 18.5 kPa. We also know the osmotic pressure gradient across the membrane, 167 kPa. Hence: Δπ = π 2 − π 1 167 kPa = π 2 − 18.5 kPa π 2 = 185.4 kPa Now that we know the osmotic pressure of the second, more concentrated chamber, we can solve for the concentration of mannose in this chamber as follows: π 2 = gCσ RT 1 atm L-atm ⎞ ⎛ ⎞ ⎛ ⎛ 1 mol ⎞ 185.4 kPa ⎜ ⎟ = (1)C ( 0.75 ) ⎜ 0.082 ⎟ ( 298 K ) ⎜ ⎝ 101.325 kPa ⎠ ⎝ ⎝ 1000 mmol ⎟ ⎠ mol-K ⎠ 1 atm ⎛ ⎞ 185.4 kPa ⎜ ⎝ 101.325 kPa ⎟ ⎠ C= L-atm ⎞ ( 0.75 ) ⎛ 0.082 ⎜ ⎟ ( 298 K ) ⎝ mol-K ⎠ C = 0.0999 mol L Since there is one 1L in each compartment, there’s 0.09...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern