This preview shows page 1. Sign up to view the full content.
Unformatted text preview: hose partition coefficient is 1/3 that of glucose’s. What would be the steady state flow across the membrane? (10) Solution: Reconsider the equation for net rate of diffusion where J1 is the original rate of diffusion of glucose and J2 is the second molecule V : J = PA ( C A − C B )
kD
(CA − CB )
Δx
⎛ k⎞
⎜ ⎟ (2 D)
⎝ 3⎠
J2 =
(CA − CB ) Δx
2 ⎡ kD
⎤
J 2 = ⎢ (CA − CB )⎥
3 ⎣ Δx
⎦
2
J 2 = J1
3
2
2⎛
mol ⎞
−13 mol
Hence, J 2 = J1 = ⎜ 2.013 × 10 −13 ⎟ = 1.34 × 10
3
3⎝
s⎠
s
J1 = QUESTION 4 A 35 year old woman comes to your clinic for a routine checkup. Her vital signs are as follows: T=37 ºC, HR=72 beats/min, BP 125/65 mmHg. (30 total) A. What are this woman’s pulse pressure and mean arterial pressure (in mmHg)? (10) Solution: From the given blood pressure, we know that...
View Full
Document
 Spring '13
 SanjayKumar

Click to edit the document details