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Unformatted text preview: r adj = 125 m. rad m m r adj adj 2 / 500 125 2 2 π λ δ = = Δ = Δ . So, phasor diagram looks like: (b) The three phasors form three sides of a square, so the sum of the vectors is the fourth side of the square – has the same amplitude A tot = A. A A A tot Δδ = π /2 A Δδ = π /2 Tipler Problem 3364 “5 th order” means 5 th side maximum, so Δδ adj = 10 π . λ π δ 5 2 10 2 = = Δ = Δ adj adj r We are far away, so Δ r adj = dsin θ , so 5 λ =dsin θ ....
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This note was uploaded on 04/07/2008 for the course PHYS 212 taught by Professor Ladd during the Spring '08 term at Bucknell.
 Spring '08
 Ladd

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