Hand In 7 Solutions(07)

Hand In 7 Solutions(07) - r adj = 125 m. rad m m r adj adj...

Info iconThis preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Hand-in Set #7, Due Monday March 5, 2007 A40, A46, A104, A105; CH 33: 30, 36, 46, 52a, 64 Note: for A40 here, don’t worry about the issues of Δδ ref Æ that was relevant last year, but we dropped it for the material this year.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
(a) The phase difference 2 / 2 5 . 0 2 2 π λ = = Δ = Δ r since the waves are shifted by ¼ of a wavelength with respect to each other (0.5 shift and wavelength 2). So, phasor diagram is as follows: (b) Right triangle, so = + = 2 2 2 2 tot A 2.8 2 2 A tot Δδ = π /2
Background image of page 2
(a) For this problem, Δ r adj is simply the distance between the towers Æ Δ
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: r adj = 125 m. rad m m r adj adj 2 / 500 125 2 2 = = = . So, phasor diagram looks like: (b) The three phasors form three sides of a square, so the sum of the vectors is the fourth side of the square has the same amplitude A tot = A. A A A tot = /2 A = /2 Tipler Problem 33-64 5 th order means 5 th side maximum, so adj = 10 . 5 2 10 2 = = = adj adj r We are far away, so r adj = dsin , so 5 =dsin ....
View Full Document

Page1 / 7

Hand In 7 Solutions(07) - r adj = 125 m. rad m m r adj adj...

This preview shows document pages 1 - 7. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online