# E f q m c t 10 g 202 jgc 40c 808 j total

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Unformatted text preview: (E-F). Q = m c ∆T = (10 g) (2.02 J/g°C) ( 40°C) = 808 J Total heat for converting 10 g of solid ice at -20°C to 10 g of gaseous steam at 140°C is the sum of all steps. QTot = 420J + 3400J + 4200J + 22700 J + 808 J = 31,528 J Practice Problems Calculate the total heat energy needed to convert 100 g of ice at -10°C to steam at 110°C. CHEMISTRY HEATING CURVE WORKSHEET Heating Curve of Substance X 85 80 75 70 V 65 60 IV 55 Temp. (°C) 50 45 40 35 III 30 25 20 15 10 II 5 0 I -5 -10 -15 -20 0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 Time (Minutes) The heating curve shown above is a plot of temperature vs time. It represents the heating of substance X at a constant rate of heat transfer. Answer the following questions using this heating curve: ______1. In what part of the curve would substance X have a definite shape and definite volume? ______2. In what part of the curve would substance X have a definite volume but no definite shape? ______3. In what part of the curve would substance X have no definite shape or volume? ______4. What pa...
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## This document was uploaded on 01/20/2014.

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