EE1002 Notes Part1

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Unformatted text preview: elements connected to it or the negative end of a voltage source is taken as the reference node. Assigning node voltages Label the node voltages as v1 , v2 ,..etc. which are with respect to the reference node. Writing KCL equations in terms of the node voltages We need as many independent equations as the number of unknowns. These are obtained by applying KCL at each node. KCL states that the algebraic sum of currents leaving a node is equal to zero. To find the current leaving the node n through each resistor connected to the node k, we subtract the voltage at node k from the voltage at node n and divide the difference by the resistance. I nk vn vk Rnk Applying KCL at node 2, 35 EE1002 Introduction to Circuits and Systems v2 v1 v2 v2 v3 0 R2 R4 R3 (1) Applying KCL at node 3, sum of currents leaving the node equals zero. v3 v1 v3 v2 v3 0 R1 R3 R5 (2) At node 1, we cannot apply KCL as not all branches connected to this node are resistors. We cannot find the current through a voltage source by applying...
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## This document was uploaded on 01/20/2014.

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