Is at at high frequencies the impedance of the

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Unformatted text preview: of the output current to ground. ⎛ྎ 1 ⎞ྏ ⎟ྏ Av = − g m ⎜ྎ RC || ⎜ྎ jωCL ⎟ྏ ⎝ྎ ⎠ྏ EE105, Fall 2013 Lecture 13 – Slide 4 Prof. Ming C. Wu 2 Frequency Response of the CE Stage §༊  At low frequency, the capacitor is effecDvely an open circuit, and Av vs. ω is flat. At high frequencies, the impedance of the capacitor decreases and hence the gain decreases. The “breakpoint” frequency is 1/(RCCL). 1 RC jωCL 1 RC + jωCL Av = − g m = Av = EE105, Fall 2013 − g m RC 1 + jω RC CL g m RC 2 C 2 R CLω 2 + 1 Lecture 13 – Slide 5 Prof. Ming C. Wu Amplifier Figure of Merit (FOM)...
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