Lecture 21

# Lecture 21 slide 5 ee105 fall 2013 prof ming c wu

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: L Prof. Ming C. Wu 2 Dealing with a FloaFng Capacitance §༊  Recall that a pole is computed by ﬁnding the resistance and capacitance between a node and (AC) GROUND. §༊  It is not straighRorward to compute the pole due to CF in the circuit below, because neither of its terminals is grounded. Lecture 21 – Slide 5 EE105, Fall 2013 Prof. Ming C. Wu Miller’s Theorem §༊  If Av is the voltage gain from node 1 to 2, then a ﬂoaFng impedance ZF can be converted to two grounded impedances Z1 and Z2: V1 − V2 V1 V1 1 = ⇒ Z1 = Z F = ZF ZF Z1 V1 − V2 1 − Av V1 − V2 V =− 2 ZF Z2 EE105, Fall 2013 ⇒ Z2 = −ZF V2 1 = ZF V1 − V2 1 − 1 / Av Lecture 21 – Slide 6 Prof. Ming C. Wu 3 Miller MulFplicaFon §༊  Applying Miller’s theorem, we can convert a ﬂoaFng capacitance between the input and output nodes of an ampliﬁer into two grounded capacitances. §༊  The capacitance at the input node is larger than the original ﬂoaFng capacitance. Z2 = Z1 = ZF...
View Full Document

Ask a homework question - tutors are online