Lecture 21

Lecture 21 - Lecture 21 Frequency Response Review of basic...

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1 Lecture 21 – Slide 1 EE105, Fall 2013 Prof. Ming C. Wu Lecture’21’ § Frequency Response Review of basic concepts high-frequency MOSFET model CS stage CG stage Source follower Cascode stage § Reading: Chapter 11 Lecture 21 – Slide 2 EE105, Fall 2013 Prof. Ming C. Wu A v ’Roll-Of’due’to’ C L § The’impedance’oF’ C L ’decreases’at’high’Frequencies,’so’that’it’ shunts’some’oF’the’output’current’to’ground.’ § In’general,’iF’node’ j ’in’the’signal’path’has’a’small-signal’ resistance’oF’ R j ’to’ground’and’a’capacitance’ C j ’to’ground,’ then’it’contributes’a’pole’at’Frequency’( R j C j ) -1’ L D p C R 1 = ω 0 = λ 1 || 1 vm D L D m DL Ag R jC R g jRC ΛΞ = ΜΟ ΝΠ = +
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2 Lecture 21 – Slide 3 EE105, Fall 2013 Prof. Ming C. Wu Pole’IdenFfcaFon’Example’1’ in G p C R 1 1 = ω L D p C R 1 2 = 0 = λ Lecture 21 – Slide 4 EE105, Fall 2013 Prof. Ming C. Wu Pole’IdenFfcaFon’Example’2’ in m G p C g R Ο Ο Π Ξ Μ Μ Ν Λ = 1 || 1 1 L D p C R 1 2 = 0 =
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3 Lecture 21 – Slide 5 EE105, Fall 2013 Prof. Ming C. Wu Dealing’with’a’Floafng’Capacitance’ § Recall’that’a’pole’is’computed’by’±nding’the’resistance’and’ capacitance’between’a’node’and’(AC)’GROUND.’ § It’is’not’straigh²orward’to’compute’the’pole’due’to’ C F ’in’the’ circuit’below,’because’neither’o³’its’terminals’is’grounded.’ Lecture 21 – Slide 6 EE105, Fall 2013 Prof. Ming C. Wu Miller s’Theorem’ § I³’ A v’ is’the’voltage’gain’³rom’node’1’to’2,’then’a’ floafng’impedance’ Z F’ can’be’converted’to’two’ grounded’impedances’Z 1’ and’Z 2 :’ v F F F A Z V V V Z Z Z V Z V V = = = 1 1 2 1 1 1 1 1 2 1 V 1 V 2 Z F = V 2 Z 2 Z 2 = Z F V 2 V 1 V 2 = Z F 1 1 1/ A v
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4 Lecture 21 – Slide 7 EE105, Fall 2013 Prof. Ming C. Wu Miller’MulFplicaFon’
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Lecture 21 - Lecture 21 Frequency Response Review of basic...

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