Midterm Exam 1 Solutions 08

01 v 099 v 1 ln 836 mv 1 ii is the bjt in the active

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Unformatted text preview: on is reverse biased (i.e., ). iii) Find the small signal parameters of the BJT under this bias condition. [4 pts] 1 26 38.5 mS 2.6 kΩ 10 kΩ Page 7 iv) What is the expression for the voltage gain? What is its numerical value? [6 pts] For this part, assume ∞ (given during exam). 9.65 1 1 You could also write the gain as the gain from the input to the base times the gain from the base to the collector, which would look like: 1 1 1 9.65 v) What is the expression for the input impedance (seen by vin )? What is its numerical value? [6 pts] For this part, assume ∞ (given during exam). 1 Page 8 104.6 kΩ vi) What is the expression for the output impedance (seen by vout )? What is its numerical value? [6 pts] For this circuit, we must perform small-signal analysis to determine the output resistance. The derivation is similar to the derivation of the output impedance of a common emitter amplifier with emitter degeneration. Here’s the small-signal model with a test source at the output (excluding obviously goes in parallel with the result from this analysis): , which 1 1 1 1 1 Page 9 9.58 kΩ...
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